-16x^2+136x=0

Solution for -16x^2+136x=0 equation:

-16x^2+136x=0

a = -16; b = 136; c = 0;
Δ = b2-4ac
Δ = 1362-4·(-16)·0
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(136)-136}{2*-16}=\frac{-272}{-32}
=8+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(136)+136}{2*-16}=\frac{0}{-32}
=0
$